2nd Scribe

Okay, so i'm the second scribe. We didn't do that much today since the lesson was yesterday afternoon. We just did the question #8 in the exercises as well as #11.

Question 8:

Given the sketch of g(x) = f(x + 2) + 1, sketch f(x):



The question simply asks that in the given graph, sketch the graph where it originally came from.

So we can start in the inside bracket. It says f(x + 2) + 1. To go to the original point, instead of shifting to the left by 2 units, it will be 2 units to the right.




After shifting to the right, the next is the f(x + 2) + 1. Instead of shifting it up by 1 unit, the points are going to be shifted down by 1 unit.


And this is f(x).

Question #11.
Find the approximate values of the equation 3sin² ϑ + 5sin ϑ - 2 = 0 for 0< ϑ<2 π.

First, it is easy for me to just substitute 'x' to 'sin ϑ'. It is going to be like factoring an equation.
3x² + 5x - 2 = 0.

Factor:
(3x-1)(x+2)

Substitute:
(3sin ϑ - 1)(sin ϑ + 2)

Solve:

3sin ϑ = 1
sin ϑ = 1/3
ϑ = 19.5^o ; 160.5^o

sin ϑ = 2
no solution


I hope i did it right. Considering it should be easy. Ok, well the next scribe would be Bale! (Ms. Ingram said. =P)